72x^2-336x+150=0

Solution for 72x^2-336x+150=0 equation:

72x^2-336x+150=0

a = 72; b = -336; c = +150;
Δ = b2-4ac
Δ = -3362-4·72·150
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{69696}=264$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-336)-264}{2*72}=\frac{72}{144}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-336)+264}{2*72}=\frac{600}{144}
=4+1/6
$